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Exam Code: NSE5_FCT-7.0 (Updated 60 Q&As)
Exam Name: Fortinet NSE 5 - FortiClient EMS 7.0
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NEW QUESTION: 1
You are performing a code review for Transact-SQL statements.
What action does the constraint in each statement perform? To answer, select the appropriate options in the answer area.
NOTE: Each correct selection is worth one point.

Answer:
Explanation:




NEW QUESTION: 2
Ein Techniker identifiziert ein falsch terminiertes Netzwerkkabel als Ursache für intermittierende Netzwerkabfälle. Welches der folgenden Tools sollte der Techniker verwenden, um das Netzwerkkabel zu bestimmen?
A. Ein Loopback-Stecker
B. Eine Crimper
C. Ein Kabeltester
D. Ein Multimeter
Answer: C

NEW QUESTION: 3

A. Option C
B. Option B
C. Option D
D. Option A
Answer: D

NEW QUESTION: 4
Refer to the exhibit.

Which two statements are true? (Choose two.)
A. Router R1 will advertise connected and summary routes only.
B. The eigrp stub command will automatically enable summarization of routes on R2.
C. The eigrp stub command prevents all routes except a default route from being advertised to R1.
D. Router R1 will advertise connected and static routes. The sending of summary routes will not be permitted.
E. Router R1 is configured as a receive-only neighbor and will not send any connected, static or summary routes.
F. The eigrp stub command prevents queries from being sent from R2 to R1.
Answer: A,F
Explanation:
Explanation The command "eigrp stub" turns R1 into a stub router so R2 will never send any query to R1 because R2 knows that a stub router will only route packets for networks it has explicitly advertised. The command "eigrp stub" is same as "eigrp stub connected summary" command because connected and summarized routes are advertised by default. Note: Because the network 192.168.50.0 is not advertised by "network" statement, it is necessary to redistribute connected route with the "redistribute connected" command.


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