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NEW QUESTION: 1

A. Option D
B. Option C
C. Option A
D. Option B
Answer: A

NEW QUESTION: 2
A company has placed a networked PC in a lobby so guests can have access to the corporate directory.
A security concern is that someone will disconnect the directory PC and re-connect their laptop computer and have
access to the corporate network. For the port servicing the lobby, which three configuration steps should be
performed on the switch to prevent this? (Choose three.)
A. Enable port security.
B. Create the port as a protected port.
C. Create the port as an access port.
D. Statically assign the MAC address to the address table.
E. Create the port as a trunk port.
F. Configure the switch to discover new MAC addresses after a set time of inactivity.
G. Set the port security aging time to 0.
Answer: A,C,D
Explanation:
If port security is enabled and the port is only designated as access port, and finally static MAC address is assigned, it
ensures that even if a physical connection is done by taking out the directory PC and inserting personal laptop or
device, the connection cannot be made to the corporate network, hence ensuring safety.

NEW QUESTION: 3
Refer to the exhibit. Customer is planning to deploy a clustering over the WAN UCM topology with 2 subscribers at site 1 and 2 subscribers at site 2.
How much bandwidth would be required between site 1 and site 2 to for database replication?

A. 1.544 Mbps
B. 4.632 Mbps
C. 3.088 Mbps
D. 7.772 Mbps
E. 6.176 Mbps
Answer: B
Explanation:
Consider two sites, Site 1 and Site 2, with Unified CM clustered over the WAN across these two sites that are 80 msec round-trip time apart. Site 1 has one publisher, one combined TFTP and music on hold (MoH) server, and two Unified CM subscriber servers. Site 2 has one TFTP/MoH server and two Unified CM subscriber servers. Site 1 has 5000 phones, each having one DN; and Site 2 has 5000 phones, each having one DN. During the busy hour, 2500 phones in Site 1 call
2500 phones in Site 2, each at 3 BHCA. During that same busy hour, 2500 phones in Site 2 also call 2500 phones in Site 1, each at 3 BHCA. In this case:
Total BHCA during the busy hour = 2500*3 + 2500*3 = 15,000
Total bandwidth required between the sites = Total ICCS bandwidth + Total database bandwidth Because total BHCA is 15,000 (greater than 10,000), we can use the formula to calculate:
Total ICCS bandwidth = (15,000/10,000) * (1 + 0.006*80) = 2.22 Mbps
Total database bandwidth = (Number of servers remote to the publisher) * 1.544 = 3 * 1.544 =
4.632 Mbps
http://www.cisco.com/c/en/us/td/docs/voice_ip_comm/cucm/srnd/7x/uc7_0/models.html

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